wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

For each tR, let [t] be the greatest integer less than or equal to t. Then, limx1+(1|x|+sin|1x|)sin(π2[1x])|1x|[1x]

A
equals 0
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
B
equals 1
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
equals 1
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
does not exist
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is A equals 0
L=limx1+(1|x|+sin|1x|)sin(π2[1x])|1x|[1x]
x1+x>1[1x]=1,|1x|=x1
L=limx1+(1x+sin(x1))sin(π2(1))(x1)(1)
=limx1+(1sin(x1)x1)(1)
=1+1=0

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Standard Expansions and Standard Limits
MATHEMATICS
Watch in App
Join BYJU'S Learning Program
CrossIcon