For equation $4 x + 5 y = 19$ if $x = 1$ , find the value of $y$ .

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Solution

A] Given, 4x + 5y = 19
x = 1
substituting,
4 (1) + 5y = 19
= 5y = 19 - 4
= 5y = 15
$∴ y = 3$

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