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Question

For equation given below, find the value of 'm' so that the equation has equal roots. Also find the solution of equation:

(m-3)x2 - 4x + 1 = 0

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Solution

Equation has equal roots when b^2-4ac =0
here
a=m-3
b=-4
c=1
then b^2-4ac=16-4*(m-3)*1
=16-4m+12
equate it to zero
28-4m=0
28=4m
m=7

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