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Question

For every natural number n, n(n+3) is always :

A
multiple of 4
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B
multiple of 5
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C
even
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D
odd
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Solution

The correct option is B even
n(n+3)=n2+3n+22=(n+1)(n+2)2eveneveneven
Since for any natural number n, (n+1)(n+2) will always be an even number.

OR

We know there are two types of natural numbers even and odd

Case 1. If n is even then n+3 will be odd

Thus n(n+3)= even × odd = even

Case 2. If n is odd then n+3 will be even

Thus n(n+3)= odd × even = even

Hence n(n+3) will always be even number

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