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Question

For every ,one 37Cl isotope there are three 35Cl isotopes, in a sample of chlorine. What will be the average atomic mass of chlorine?

A
35
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B
37
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C
35.5
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D
35.6
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Solution

The correct option is C 35.5
Average atomic mass of an element existing in different isotopes is given by:
Mavg=ni=1MiAini=1Ai
where Mi=atomic mass of an isotope with relative abundance of Ai
Given:M1=37u,A1=1,M2=35u,A2=3
on subtitutiing we get:
Mavg=37×1+35×31+3
Mavg=35.5 u
option C is correct

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