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Question

For every pair of number x and y the function f satisfies 2f(x-y)= f(x)f(y) then the value of f(2) isa.2b.1/2c.0d.4

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Solution

Dear Student,

Given That 2f(x-y)=f(x)f(y)
Let x=2 , y = 1 => 2f(2-1)=f(2)f(1)
2f(1)= f(2)f(1)
Dividing both side by f(1) we get
=> f(2)=2
Hence our Answer is a).2

Regards

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