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Torque Due to Gravity

For F1 = 30...

Question

For $F_{1} = 300 N$ and $F_{2} = 100 N$ , find the direction and magnitude of friction force acting on the block.

180 N, vertically upwards

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40 N, vertically upwards

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107.7 N making an angle of

{tan}^{- 1} (\frac{2}{5})

with the horizontal in the upward direction.

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91.6 N making an angle of

{tan}^{- 1} (\frac{2}{5})

with the horizontal in the upward direction.

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Solution

The correct option is D 107.7 N making an angle of ${tan}^{- 1} (\frac{2}{5})$ with the horizontal in the upward direction.
REF.Image.
$f_{r m a x}$ available = 130 N (0.60 )
thus, block does not fall.
$t a n θ = 2 / 5$
friction = 107.7N in direction upwards from horizontal by angle $t a n^{- 2} 2 / 5.$

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For F1=300N and F2=100N, find the direction and magnitude of friction force acting on the block.

The correct option is D 107.7 N making an angle of tan−1(25) with the horizontal in the upward direction.REF.Image.frmax available = 130 N (0.60 )thus, block does not fall.tanθ=2/5friction = 107.7N in direction upwards from horizontal by angle tan−22/5.

For $F_{1} = 300 N$ and $F_{2} = 100 N$ , find the direction and magnitude of friction force acting on the block.