For $f (x) = {log}_{e^{n}} x^{n}$ then find $(f^{'} (1))$

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Solution

$f (x) = {log}_{e^{n}} x^{n} f (x) = {log}_{e} x f^{'} (x) = \frac{1}{x} f^{'} (1) = 1$

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For f(x)=logenxn then find (f′(1))

f(x)=logenxnf(x)=logexf′(x)=1xf′(1)=1

For $f (x) = {log}_{e^{n}} x^{n}$ then find $(f^{'} (1))$

$f (x) = {log}_{e^{n}} x^{n} f (x) = {log}_{e} x f^{'} (x) = \frac{1}{x} f^{'} (1) = 1$