For ∫f(x)dx=F(x)+C, if ∫4f(2x+3)dx=aF(2x+3)+C, then the value of a is
A
2
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B
3
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C
4
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D
8
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Solution
The correct option is A 2 For any integrable function f(x), such that ∫f(x)dx=F(x)+C
We know that ∫kf(x)dx=kF(x)+C
and ∫f(ax+b)dx=1aF(ax+b)+C
Thus combining these two properties we get: ∫kf(ax+b)dx=kaF(ax+b)+C
Now we can write our integral as: ∫4f(2x+3)dx=42F(2x+3)+C