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Function

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Question

For function f(x) = 1/x, the value of domain can't be ____

A

0

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B

2

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C

1

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D

-1

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Solution

The correct option is A 0
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Similar questions

Q. A function f(x, y) is defined for non - negative integers
I. f(0, 0) = 0
II. f(2x, 2y) = f(2x + 1, 2y + 1) = f(x, y)
III. f(2x + 1, 2y) = f(2x, 2y + 1) = f(x, y) + 1
What is the value of f(11, 5)?

f (x)

f^{2} (x) - f^{2} (y) = 4 (x - y)

f (0) = 2 (f (x) \geq 0)

whose domain is

[a, \infty)

and it is differentiable on

(a, \infty)

f (3)

f (x)

f^{2} (x) - f^{2} (y) = 4 (x - y)

f (0) = 2 (f (x) \geq 0)

whose domain is

[a, \infty)

and it is differentiable on

(a, \infty)

The value of definite integral

\int_{a}^{0} f (x) d x

f : R \to R

be a continuous function satisfying

f (0) = 1

f (2 x) - f (x) = x

x \in R .

f (2020)

f

be a continuous and differentiable function in

(a, b)

lim x \to a^{+} f (x) \to \infty

lim x \to b^{-} f (x) \to - \infty

f^{'} (x) + f^{2} (x) \geq - 1

a < x < b

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