Question

For gaseous reaction, rate $k\left[A\right]\left[B\right]$. If volume of container is reduced to $1/4$ of initial, then the rate of reaction will be _____ times of initial.

• A. $1/8$
• B. $8$
• C. $1/16$
• D. $16$

Answer 1

Answer: (D)

$16$

$r=k\left[A\right]\left[B\right]\left(\text{Given}\right)$

As we know,

Active mass $=$ concentration in moles per litre.

Therefore,

When the volume of the reaction vessel reduces to ${\frac{1}{4}}^{th}$ of its initial volume, the molar concentration of each reactant increases four times.

$\therefore r^{\prime }=k\left[4A\right]\left[4B\right]=16k\left[A\right]\left[B\right]=16r$

Hence the rate of reaction will be $16$ times of initial.

Hence, the correct option is $D$