For gaseous state, if the most probable speed is denoted by C∗, average speed by ¯C and root mean square speed by C, then for a large number of molecules, the ratios of these speeds are:
Kinetic gas equation :
PV=13mN¯u2
Volume of container(V)=l3
Verification of gas laws with kinetic gas equation :
PV=13mN¯u2.......................(1)
According to Kinetic theory of gases :
12m¯u2rms=λT (in kelvin).................(2)
where λ is a proportionality constant.
Multiply and divide equation 1 by 2 on both sides :
PV=2312mN¯u2................(3)
From equation (2) 12m¯u2rms=λT.......(4)
Putting the value of equation 4 in equation 3 :
PV=23(λT)N
P∝1V which is Boyle's law at constant N and T.
Similarly we can prove charles’ law from kinetic gas equation :
At constant N and Pressure(P):
V∝T and similarly it can be done at constant N and Volume (V) which is Gay lussac’s law :
P∝T
At constant temperature (T) and Pressure (P) Kinetic gas equation can prove Avogadro’s law :
V∝N or V=k3N
Dividing and multiplying by NA
V=k3NA(NNA) or V=k4(NNA)
Calculation of λ :
From ideal gases :
PV=nRT=23λNT........(1)
Where n=number of moles of gas andNA=Avogadro′s number
Since number of moles(n)=Given number of molecules(N)Avogadro′s number(NA)
N=nNA...........(2)
Putting the value of N from 2 in 1 :
PV=nRT=23(nNA)λT
λ=32RNA or λ=32k where k is Boltzmann constant
k(Boltzmann constant)=RNA
Average kinetic energy of molecules :
12m¯u2rms∝T(in kelvin)or 12m¯u2rms=λT(in kelvin) where λ is a proportionality constant.
λT=32kT where k is Boltzmann constant
k=1.38×10−23 JK−1
Total Kinetic energy per mole :
Total kinetic energy=NA(12m¯u2rms)=NA(λT)
=32(RNA)NA=32R
Root mean square speed Vrms :
Total kinetic energy=12M¯u2rms=32RT
¯u2rms=3RTM or ¯urms=2√3RTM
Unit of urms:
Unit of urms=√(J K−1 mol−1)(K)kg mol−1
Unit of urms=√Jkg
Unit of urms=√kg m2 s−2kg
Unit of urms=m s−1
Note: Always take R in J K−1 mol−1 and M in kg mol−1