Question

For given energy of photon, $E=3.03\times {10}^{-19}J$ corresponding wavelength will be:

$(h=6.6\times {10}^{-34}sec$, $C=3\times {10}^{8}m/sec.)$

• A. 65.6 nm
• B. 6.56 nm
• C. 3.4 nm
• D. 656 nm

Answer 1

Answer: (D)

656 nm

$E=3.03\times {10}^{-19}J$

First we use is:

$\lambda =\frac{hc}{E}$

$=\frac{6.6\times {10}^{-34}\times 3\times {10}^8}{3.03\times {10}^{-19}}m$

$=656nm$

Therfore we will get the corresponding wavelength.