For given shape of wave at time t=t0, velocity of particle at x=x0 is twice the wave velocity of given transverse wave. Find the slope of wave at x=x0.
A
2
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B
−2
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C
1
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D
−1
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Solution
The correct option is B−2 The particle velocity(vP) and wave velocity(v) is related as, ⇒vP=−v×dydx....(i) wheredydx=slope of wave at a given position
At position x=x0, ⇒vP=2×v Comparing it with equation (i) gives, ⇒−dydx=2 ⇒slope of wave=dydx=−2