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Harmonic Mean

For H. P. 2...

Question

For H. P. $2, 4, 6....$ , find the value of $a_{9} =$

A

\frac{1}{18}

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B

\frac{1}{32}

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C

\frac{1}{6}

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D

\frac{1}{12}

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Solution

The correct option is A $\frac{1}{18}$
Given series is $2, 4, 6, . . . .$
Here $a = 2, d = 2$
We know $a_{n} = \frac{1}{a + (n - 1) d}$
$\Rightarrow a_{9} = \frac{1}{2 + (9 - 1) 2}$
$\Rightarrow a_{9} = \frac{1}{18}$

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