wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

For how many values of k does the following system of equations have at-least one solution?
x+y=1; kx+y=3; x+ky=5;


A

0

No worries! We‘ve got your back. Try BYJU‘S free classes today!
B

1

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
C

2

No worries! We‘ve got your back. Try BYJU‘S free classes today!
D

Infinitely many

No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is B

1


1.We have

Adding the second and third equations we get (k+1)(x+y)=8, and hence k+1=8.
Thus , k=7. The valus of x=1/3, y=2/3 satisfy the equations if k=7. Hence the answer is B.


flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Applications
MATHEMATICS
Watch in App
Join BYJU'S Learning Program
CrossIcon