Question

For how much time 48 ampere current should be passed through 400ml 0.04M Ag NO₃ solution during electrolysis so that Ag is completely deposited?

Answer 1

So basically, 400ml of 0.04M solution of AgNO3 contains 16mg of Ag+. That means , you need to get 16mg of Ag. Let's use Faraday’s law.

The atomic maas of Ag is 108, and N is 14 and O is 16.

So the molecular mass of AgNO3 is 170.

The equation is given by :

M=Zit, where, M is the amount if substance that is deposited , Z is basically equivalent weight of substance divided by F ( ~96500C), i is current passed and t is the time for which the current is passed through the solution.

Substituting:

0.016=[(107)/96500] × 48 × t.

On solving, you get :

t = ~0.3006 seconds .