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Question

For hyperbola x216y225=1 distances between two directrices are

A
1641
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B
2541
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C
±32141
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D
3241
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Solution

The correct option is D 3241
Given equation of hyperbola x216y225=1
Here a2=16,b2=25
Distance between directrix is 2a2a2+b2=2×1616+25=3241

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