Question

For hyperbola $\frac{x^2}{16}-\frac{y^2}{25}=1$, focus is is on

• A. x-axis
• B. y-axs
• C. z-axis
• D. none

Answer 1

The correct option is A x-axis

The given hyperbola $\frac{x^2}{16}-\frac{y^2}{25}=1$ is a standard form of hyperbola.

By comparing it with standard form $\frac{x^2}{a^2}-\frac{y^2}{b^2}=1$

We can know $a=4$ and $b=5$

For a standard form of hyperbola, the foci lie on the transverse axis. $i.e.$ $x$ - axis. one each side of the hyperbola, at $(ae,0)$ and $(-ae,0)$ respectively.