Question

For hyperbola $\frac{x^2}{16}-\frac{y^2}{25}=1$
vertices are

• A. $(4,4)$
• B. $(\pm 4,0)$
• C. $(\pm 4,4)$
• D. $(0,\pm 4)$

Answer 1

The correct option is B $(\pm 4,0)$

For the hyperbola of the form $\frac{x^2}{a^2}-\frac{y^2}{b^2}=1$

Vertices are $(\pm a,0)$

Given equation is $\frac{x^2}{16}-\frac{y^2}{25}=1$

So, here $a^2=16\Rightarrow a=4$

So, the vertices are $(\pm 4,0)$.