For hypothetical chemical reaction A → I, it is found that the reaction is third order in A. What happens to the rate of reaction when the concentration of A is doubled ?
A
Rate increases by a factor 2.
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B
Rate decreases by a factor 3.
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C
Rate increases by a factor 8.
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D
Rate remains unaffected.
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Solution
The correct option is C Rate increases by a factor 8. r1=k[A]3 r2=k[2A]3 Dividing equation (ii) by (i), r2=8r1