For hypothetical reaction- 4 A -5 B - 4 P -6 Q the equilibrium constant K c has units-A- mol L-1B- mol -1 LC- mol L-1-2D- Unit less

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Standard XII

Chemistry

Introduction

For hypotheti...

Question

For hypothetical reaction, $4 A + 5 B ⇌ 4 P + 6 Q$ the equilibrium constant $K_{c}$ has units:

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Solution

The correct option is A
$K_{c} = [P]^{4} [Q]^{6} = [m o l / L]^{10} = m o l L^{- 1}$
$[A]^{4} [B]^{5} [m o l / L]^{10}$

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For hypothetical reaction, 4A+5B⇌4P+6Q the equilibrium constant Kc has units:

The correct option is A Kc=[P]4[Q]6=[mol/L]10=molL−1 [A]4[B]5 [mol/L]10

For hypothetical reaction, $4 A + 5 B ⇌ 4 P + 6 Q$ the equilibrium constant $K_{c}$ has units:

The correct option is A
$K_{c} = [P]^{4} [Q]^{6} = [m o l / L]^{10} = m o l L^{- 1}$
$[A]^{4} [B]^{5} [m o l / L]^{10}$