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Byju's Answer
Standard XII
Physics
Degree of Freedom
For isotherma...
Question
For isothermal reversible expansion of an ideal gas:
A
△
H
>
0
and
△
U
=
0
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B
△
H
>
0
and
△
U
<
0
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C
△
H
=
0
and
△
U
=
0
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D
△
H
=
0
and
△
U
>
0
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Solution
The correct option is
C
△
H
=
0
and
△
U
=
0
For isothermal reversible expansion of ideal gas
Δ
H
=
0
and
Δ
U
=
0
.
For 1 mole of ideal gas,
Δ
U
=
C
v
Δ
T
=
0
. [Since
Δ
T
=
0
becuase the process is isothermal].
Again,
Δ
H
=
Δ
U
+
Δ
(
P
V
)
=
Δ
U
+
Δ
(
R
T
)
=
Δ
U
+
R
Δ
T
Δ
H
=
0
+
R
Δ
T
=
0
+
0
=
0
; [
R
Δ
T
=
0
since
Δ
T
=
0
]
Suggest Corrections
0
Similar questions
Q.
List - I
(Process)
List - II
(I) Reversible isothermal expansion of an ideal gas.
(P)
Δ
S
s
y
s
=
0
(II) Reversible adiabatic compression of a real gas.
(Q)
Δ
H
=
Δ
U
=
Δ
S
total
=
0
(III) Adiabatic free expansion
(R)
Δ
S
total
>
0
(IV) Isothermal free expansion
(S)
q
=
0
(T)
Δ
S
surr
=
0
(U)
Δ
S
s
y
s
>
0
Which of the following options has the correct combination considering List - I and List - II.
Q.
List - I
(Process)
List - II
(I) Reversible isothermal expansion of an ideal gas.
(P)
Δ
S
s
y
s
=
0
(II) Reversible adiabatic compression of a real gas.
(Q)
Δ
H
=
Δ
U
=
Δ
S
total
=
0
(III) Adiabatic free expansion.
(R)
Δ
S
total
>
0
(IV) Isothermal free expansion
(S)
q
=
0
(T)
Δ
S
surr.
=
0
(U)
Δ
S
s
y
s
>
0
Which of the following options has the incorrect combination considering List - I and List - II.
Q.
Calculate
q
,
w
,
Δ
U
for the isothermal reversible expansion of 1 mole of an ideal gas from an initial pressure of
1.0
b
a
r
to a final pressure of
0.1
b
a
r
at a constant temperature of
273
K
.
Q.
Match the column
Column - I
Column - II
(a)
Reversible cooling of an ideal gas at
(P)
w
=
0
;
q
<
0
;
Δ
U
<
0
constant volume
(b)
Reversible isothermal expansion of an
(Q)
w
<
0
;
q
>
0
;
Δ
U
>
0
ideal gas
(c)
Adiabatic expansion of non-ideal gas into
(R)
w
=
0
;
q
=
0
;
Δ
U
=
0
vacuum
(d)
Reversible melting of sulphur at normal
(S)
w
<
0
;
q
>
0
;
Δ
U
=
0
melting point
Q.
Assertion (A):
Δ
U
=
0
for a reversible as well as irreversible expansion of an ideal gas under isothermal conditions, whereas
S
t
o
t
a
l
≠
0
for an irreversible process.
Reason (R) :
Δ
U
=
0
is independent of temperature whereas
S
is proportional to temperature.
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