For $[C r C l_{3} . X N H_{3}]$ the elevation in boiling point of one molal aqueous solution is three times that of one molal aqueous solution of urea. Assuming 100% ionisation of the complex molecule and the coordination number of six, calculate the value of X.

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Solution

$Δ T_{b}$ (complex) = 3 $\times$ $Δ T_{b}$ (urea)
Thus, complex should furnish 3 ions. Therefore, ccomplex is
$[C r C l . x N H_{3}] C l_{2} \to [C r C l . x N H_{3}]^{2 +} + 2 C l^{-}$
Also, coordination number of $C r$ is six
Thus,
x = 5

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For [CrCl3.XNH3] the elevation in boiling point of one molal aqueous solution is three times that of one molal aqueous solution of urea. Assuming 100% ionisation of the complex molecule and the coordination number of six, calculate the value of X.

ΔTb(complex) = 3× ΔTb (urea) Thus, complex should furnish 3 ions. Therefore, ccomplex is [CrCl.xNH3]Cl2→ [CrCl.xNH3]2++ 2Cl− Also, coordination number of Cr is six Thus, x = 5

For $[C r C l_{3} . X N H_{3}]$ the elevation in boiling point of one molal aqueous solution is three times that of one molal aqueous solution of urea. Assuming 100% ionisation of the complex molecule and the coordination number of six, calculate the value of X.

$Δ T_{b}$ (complex) = 3 $\times$ $Δ T_{b}$ (urea)
Thus, complex should furnish 3 ions. Therefore, ccomplex is
$[C r C l . x N H_{3}] C l_{2} \to [C r C l . x N H_{3}]^{2 +} + 2 C l^{-}$
Also, coordination number of $C r$ is six
Thus,
x = 5