For lines of regression 4x-2y=3 and 2x-3y=5 , find $b_{y x}$

\frac{2}{3}

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\frac{1}{3}

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\frac{- 2}{3}

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\frac{- 1}{3}

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Solution

The correct option is A $\frac{2}{3}$
$= 2 x - 3 y = 5$
$\Rightarrow y = \frac{- 5}{3} + \frac{2}{3} x$
so,
$b_{y x} = \frac{2}{3}$

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Similar questions

Q. For lines of regression 4x-2y=3 and 2x-3y=5 , find

b_{x y}

Q. For lines of regression 4x-2y=3 and 2x-3y=5 , find y when

x = 3

Q. Find the coefficient of correlation from the regression lines:

x - 2 y + 3 = 0

and

4 x - 5 y + 1 = 0

Q. The distance between lines

\frac{3 x - 2}{6} = \frac{4 y - 3}{12} = \frac{4 x - 3}{8}

and

\frac{2 x - 1}{2} = \frac{3 y - 2}{2} = \frac{4 z - 3}{- 8}

Which of the following pairs of linear equations is inconsistent?
$1. x + 3 y - 5 = 0, 2 x + y = 0$
$2. 2 x + y = 1, 2 y = 2 - 4 x$
$3. 2 x - y = 2, 2 y - 4 x = 2$

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For lines of regression 4x-2y=3 and 2x-3y=5 , find byx

The correct option is A 23=2x−3y=5⇒y=−53+23xso,byx=23

For lines of regression 4x-2y=3 and 2x-3y=5 , find $b_{y x}$

The correct option is A $\frac{2}{3}$
$= 2 x - 3 y = 5$
$\Rightarrow y = \frac{- 5}{3} + \frac{2}{3} x$
so,
$b_{y x} = \frac{2}{3}$