For lines of regression 4x-2y=3 and 2x-3y=5 , find y when $x = 3$

\frac{1}{3}

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\frac{4}{3}

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\frac{- 1}{3}

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\frac{- 44}{3}

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Solution

The correct option is A $\frac{1}{3}$
$= 2 x - 3 y = 5$
$\Rightarrow x = 3$
$\Rightarrow 6 - 3 y = 5$
$\Rightarrow y = \frac{1}{3}$

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Similar questions

b_{x y}

b_{y x}

x - 2 y + 3 = 0

4 x - 5 y + 1 = 0

x	$1$	$2$	$3$	$4$	$5$
y	$7$	$6$	$5$	$4$	$3$

x = 6

\frac{3 (y - 5)}{4} - \frac{44}{1} = 3 - (\frac{y - 3}{2})

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