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Question

For loop ABCDA, B.di will be?

A
equals to 4μ0
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B
greater than 4μ0
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C
less than 4μ0
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D
None of the above
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Solution

The correct option is C less than 4μ0
B.di=μ0(ic+id)
=μ0(ic+ϵ0dϕEdt)
=μ0(813+(ve))
=μ0(4ve)
<μ0(4)
ic = Conducting current
id = displacement current

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