For Mendelian dominance, a man is homozygous and woman is heterozygous for a disease. What is the percentage of their homozygous children for the said trait?
A
50
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B
100
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C
25
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D
75
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Solution
The correct option is A 50 Parent generation : AA (father) X Aa (mother)
Gametes : AA----> Aa
A
A
A
AA
AA
a
Aa
Aa
F1 generation, genotype ratio is 1 AA (homozygous dominant) : 1 (heterozygous dominant). Thus, percentage of their homozygous children for the said trait is 50%.