Question

For$N_2{O}_4\rightleftharpoons {2NO}_2$, $K_p=X$ when initial pressure of $N_2{O}_4$ is 2 atm. If the initial pressure of $N_2{O}_4$ at same $T$ is $6atm$, $K_p$ is:

• A. $\frac{X}{3}$
• B. $3X$
• C. $X^3$
• D. $X$

Answer 1

The correct option is D $X$

K${}_p$ ( Equilibrium constant ) of the reaction doesn't depend on the pressure of system .

So, Even when initial pressure of $N_2{O}_4$ is 6 atm, K${}_p$ = X .