For n-25- x-125- x2-650- y-100- y2-460- xy-508- correlation coefficient is

The correct option is B 0.207 n=25 ∑ x=125, ∑x^2=650, ∑xy=334 #160; ∑ y=100, ∑y^2=508 r= n∑ xy (∑ x ×∑ y ) √( (n∑ x ^ ...

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Standard IX

Mathematics

Standard Deviation about Mean

For n=25,∑ ...

Question

For $n = 25, \sum x = 125, \sum x^{2} = 650, \sum y = 100, \sum y^{2} = 460, \sum x y = 508$ , correlation coefficient is

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0.207

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0.66

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0.89

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Solution

The correct option is B $0.207$
$n = 25$
$\sum x = 125, \sum x^{2} = 650, \sum x y = 334$ $\sum y = 100, \sum y^{2} = 508$
$r = \frac{n \sum x y - (\sum x \times \sum y)}{\sqrt{(n \sum x^{2} - \sum x^{2}) (n \sum y^{2} - \sum y^{2})}} = \frac{25 \times 508 - 100 \times 125}{\sqrt{(25 \times 650 - 125^{2}) (25 \times 460 - 100^{2})}} = 0.207$

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For n=25,∑x=125,∑x2=650,∑y=100,∑y2=460,∑xy=508, correlation coefficient is

The correct option is B 0.207n=25∑x=125,∑x2=650,∑xy=334 ∑y=100,∑y2=508r=n∑xy−(∑x×∑y)√(n∑x2−∑x2)(n∑y2−∑y2)=25×508−100×125√(25×650−1252)(25×460−1002)=0.207

For $n = 25, \sum x = 125, \sum x^{2} = 650, \sum y = 100, \sum y^{2} = 460, \sum x y = 508$ , correlation coefficient is