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for N2 +3H2 =...

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for N2 +3H2 =2NH3 △ H=-93.6KJ/MOLE. THE CONCENTRATION OF H2 AT EQUILIBRIUM INCREASES IF forN2+3H2=2NH3\bigtriangleup H=-93.6KJ/MOLE.THECONCENTRATIONOFH2ATEQUILIBRIUMINCREASESIF a\} Tempreture descreases. b\} N2 is added at cons†an t volume c\} NH3 is removed d\} volume of system descreased

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N_{2} + 3 H_{2} ⇌ 2 N H_{3}, K_{c}

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N_{2} + 3 H_{2} ⇌ 2 N H_{3}, K_{6}

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N_{2} + 3 H_{2} ⇌ 2 N H_{3}

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