For $N H_{4} H S (s) ⇌ N H_{3} (g) + H_{2} S (g)$ . If $K_{P} = 64 a t m^{2}$ . Equilibrium pressure of mixture is:

8 a t m

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16 a t m

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64 a t m

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4 a t m

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Solution

The correct option is B $16 a t m$
${N H}_{4} H S (s) ⇌ {N H}_{3} (g) + H_{2} S (g) K_{P} = 64 {a t m}^{2}$
$0$ $0$ $0$
$a - x$ $x$ $x$

$\Rightarrow K_{P} = x^{2} = 64 a t m^{2} x = 8 a t m$

total pressure at Eq $\Rightarrow 8 + 8 = 16 a t m$

Option B is correct.

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