You visited us 1 times! Enjoying our articles? Unlock Full Access!

Byju's Answer

Standard XII

Chemistry

Introduction to d and f Block Elements

For Ni and ...

Question

For $N i$ and $P t$ different I.P in $k J$ ${m o l}^{- 1}$ are given below:

${(I P)}_{1} + {(I P)}_{2}$ ${(I P)}_{3} + {(I P)}_{4}$
$N i$ $2.49$ $8.80$
$P t$ $2.60$ $6.70$

Choose the correct statement.

nickel

(I I)

compounds tend to be thermodynamically more stable than platinum

(I I)

No worries! We‘ve got your back. Try BYJU‘S free classes today!

platinum

(I V)

compounds tend to be more stable then nickel

(I V)

No worries! We‘ve got your back. Try BYJU‘S free classes today!

both are correct

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

none is correct

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is D both are correct
Compounds with low IP readily loose electrons to attain a more stable state. Hence nickel (II) is more stable that platinum (II) but platinum (IV) is more stable than nickel (IV).

Suggest Corrections

Similar questions

Q. For Ni and Pt different IP in

M J m o l^{- 1}

are given below

(I P)_{1} + (I P)_{2} - ------------- -

(I P)_{3} + (I P)_{4} - ------------- -

N i

2.49

8.80

P t

2.60

6.70

hence,

Q. The sum of

{I E}_{1}

and

{I E}_{2}

{I E}_{3}

and

{I E}_{4}

for

N i

and

P t

are given below

	${I E}_{1} + {I E}_{2}$	${I E}_{3} + {I E}_{4}$
$N i$	$2.49$	$8.80$
$P t$	$2.66$	$6.70$

If true enter 1, else enter 0.
It can be predicted that

{N i}^{2 +}

is more stable than

{P t}^{2 +}

Q. Assertion :

K_{2} P t C l_{6}

is well-known compound whereas corresponding

N i

compound is not known. Reason:

P t^{+ 4}

is thermodynamically more stable than

N i^{+ 4}

Q. Chooe the correct amswer using given codes. Use T if statement is true and F if it is false.
(I) Sulphide ions reacts with

N a_{2} [F e (C N)_{5} (N O)]

to form a purple coloured compound

N a_{4} [F e (C N)_{5} (N O S)]

. In the reaction, the oxidation state of iron changes.
(II)

P t (I V)

compounds are relatively more stable than

N i (I V)

compounds.
(III) The welding of magnesium can be done in the atmosphere of helium.
(IV)

L i A I H_{4}

on hydrolysis will give

H_{2}

Q. Give the correct order of initials T or F for following statements. Use T if statement is true and F if it is false.

(I)

Sulphide ions reacts with

{N a}_{4} [F e {(C N)}_{5} (N O)]

to form a purple coloured compound

{N a}_{2} [F e {(C N)}_{5} (N O S)]

. In the reaction, the oxidation state of iron changes.

(I I)

P t (I V)

compounds are relatively more stable than

N i (I V)

compounds.

(I I I)

the welding of magnesium can be done in the atmosphere of Helium

(I V)

L i A l H_{4}

on hydrolysis will give

H_{2}

Join BYJU'S Learning Program

	${(I P)}_{1} + {(I P)}_{2}$	${(I P)}_{3} + {(I P)}_{4}$
$N i$	$2.49$	$8.80$
$P t$	$2.60$	$6.70$

For Ni and Pt different I.P in kJ mol−1 are given below:(IP)1+(IP)2(IP)3+(IP)4Ni2.498.80Pt2.606.70Choose the correct statement.

The correct option is D both are correctCompounds with low IP readily loose electrons to attain a more stable state. Hence nickel (II) is more stable that platinum (II) but platinum (IV) is more stable than nickel (IV).

For $N i$ and $P t$ different I.P in $k J$ ${m o l}^{- 1}$ are given below:

${(I P)}_{1} + {(I P)}_{2}$ ${(I P)}_{3} + {(I P)}_{4}$
$N i$ $2.49$ $8.80$
$P t$ $2.60$ $6.70$

Choose the correct statement.

The correct option is D both are correct
Compounds with low IP readily loose electrons to attain a more stable state. Hence nickel (II) is more stable that platinum (II) but platinum (IV) is more stable than nickel (IV).