Question

Question 20

For non-zero numbers $a$ and $b$, ${\left(\frac{a}{b}\right)}^m÷{\left(\frac{a}{b}\right)}^n,$ where $m>n,$ is equal to:
(a)${\left(\frac{a}{b}\right)}^{mn}$
(b)${\left(\frac{a}{b}\right)}^{m+n}$
(c)${\left(\frac{a}{b}\right)}^{m-n}$
(d)${\left({\left(\frac{a}{b}\right)}^m\right)}^n$

Answer 1

We know that,
$a^m÷a^n=a^{m-n},(m>n)So,{\left(\frac{a}{b}\right)}^m÷{\left(\frac{a}{b}\right)}^n={\left(\frac{a}{b}\right)}^{m-n}$