For non-zero vectors →a and →b if |→a+→b|<|→a−→b|, then →a and →b are
A
Collinear
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B
Perpendicular to each other
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C
Inclined at an acute angle
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D
Inclined at an obtuse angle
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Solution
The correct option is B Inclined at an obtuse angle |→a+→b|<|→a−→b| a2+b2+2abcosθ<a2+b2−2abcosθ where θ is the included angle between the two vectors. Hence 4abcosθ<0 Since a,b>0 (magnitude of a vector is always a positive quantity). Hence cosθ<0 Or θ∈(π2,3π2). Hence θ is an obtuse angle.