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Question

For non-zero vectors a,b,c,(a×b).c=|a||b||c| holds if:

A
a.b=0,b.c=0
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B
b.c=0,c.a=0
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C
c.a=0,a.b=0
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D
a.b=b.c=c.a=0
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Solution

The correct option is D a.b=b.c=c.a=0
We have
(a×b).c=|a||b||c|[abc]=|a||b||c|
The above condition is possible only if a,b and c are mutually perpendicular.
So,
a.b=|a||b|cos90o=0b.c=|b||c|cos90o=0c.a=|c||a|cos90o=0
Therefore we get,
a.b=b.c=c.a=0

Hence, the correct option is D

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