For $O_{2}$ and $N_{2}$ , mention bond order.

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Solution

$N_{2} : σ 1 s^{2}, σ^{} 1 s^{2}, σ 2 s^{2}, σ^{} 2 s^{2}, (π 2 p_{y}^{2}, π 2 p_{z}^{2}), σ 2 p_{x}^{2}$
$O_{2} : σ 1 s^{2}, σ^{} 1 s^{2}, σ 2 s^{2}, σ^{} 2 s^{2}, σ 2 p_{x}^{2}, (π 2 p_{y}^{2}, π 2 p_{z}^{2}) (π^{} 2 p_{y}^{1} π^{} 2 p_{z}^{1})$
Bond order= $[(Number of e^{-} in BMO) - (Number of e^{-} in ABMO)] / 2$
$∴$ Bond order of $N_{2} = \frac{10 - 4}{2} = \frac{6}{2} = 3$ $N \equiv N$
$∴$ Bond order of $O_{2} = \frac{10 - 6}{2} = \frac{4}{2} = 2$ $O \equiv O$

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Similar questions

N_{2}, O_{2}

What is meant by the term bond order? Calculate the bond order of: $N_{2}$ , $O_{2}$ , $O_{2}^{+}$ and $O_{2}^{-}$ .

N_{2}^{+}

N_{2}

O_{2}^{+}

O_{2}

N_{2}

O_{2}

N_{2}^{+}

O_{2}^{+}

What is the effect of the following processes on the bond order in $N_{2}$ and $O_{2}$ ?

(i). $N_{2} \to N_{2}^{+} + e^{-}$

(ii) $O_{2} \to O_{2}^{+} + e^{-}$

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