Question

For one complete cycle of a thermodynamic process on a gas as shown in the $P-V$ diagram, which of following is correct.

• A. $\Delta E_{int}=0$, $Q>0$
• B. $\Delta E_{int}<0$, $Q>0$
• C. $\Delta E_{int}=0$, $Q<0$
• D. $\Delta E_{int}>0$, $Q<0$

Answer 1

The correct option is C $\Delta E_{int}=0$, $Q<0$

$\Delta E_{int}=0,$
for a complete cycle and for given cycle work done is negative, so from first law of thermodynamics $Q$ will be negative i.e., $Q<0$.
Final answer: (𝑎)