Question

For one- electron species, (IE) is given below.

$\left(IE\right)=13.6\left(\frac{Z^2}{n^2}\right)eV$

IE of ${Be}^{3+}$ is:

• A. 54.2 $eV$
• B. 122.4 $eV$
• C. 217.6 $eV$
• D. none of the above

Answer 1

The correct option is C 217.6 $eV$

For one- electron species, (IE) is given by
IE of $B{e}^{3+}$ is

$\left(IE\right)=13.6\left(\frac{4^2}{1^2}\right)eV=217.6eV$

Hence, the option (C) is the correct answer.