You visited us 1 times! Enjoying our articles? Unlock Full Access!

Real Gas Equation

For one mole ...

Question

For one mole of a van der Waal's gas when b = 0 and T = 300 K, the $p V v s \frac{1}{V}$ plot is shown below. The value of the van der Waal's constant a ( $a t m L m o l^{- 2}$ )

No worries! We‘ve got your back. Try BYJU‘S free classes today!

4.5

No worries! We‘ve got your back. Try BYJU‘S free classes today!

1.5

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is C 1.5
Van der Waal's equation of state is given as
$(p + \frac{n^{2} a}{V^{2}}) (V - n b) = n R T$
Given
$n = 1$ and $b = 0$
$(p + \frac{a}{V^{2}}) V = R T \Rightarrow p V = R T - \frac{a}{V}$
This is an equation of straight line between pV and $\frac{1}{V}$ whose slope - a.
Slope of the given graph is
$- a = \frac{20.1 - 21.6}{3 - 2} = - 1.5 \Rightarrow a = 1.5$

Suggest Corrections

Similar questions

For one mole of a van der Waal's gas when b =o and T = 300 K, the PV vs $\frac{1}{V}$ plot is shown below. The value of the Van der Waal's constant "a" ( $a t m L^{2} m o l^{- 2}$ ) is

Q. For one mole of a van der Waal's gas when b = 0 and T = 300 K, the PV vs

\frac{1}{V}

plot is shown below. The value of the van der Waal's constant a

({atm. liter}^{2} {mol}^{- 2})

is:

Q. For one mole of a van der Waal's gas when

b = 0

and

T = 300 K

, the

P V

vs.

1 / V

plot is shown below. The value of the van der Waals' constant

a

(atm.

l i t r e^{2} m o l^{- 2})

Q. For one mole of a van der Waals gas for which

b = 0

and

T = 300 K

, the

P V vs \frac{1}{V}

plot is shown below. The value of the van der Waals constant

a

(in

{atm L mol}^{- 2}

) is:

Q. For one mole of a Van der Waals gas when

b = 0

and

T = 300 K

, the

P V v s . 1 / V

plot is shown below. The value of the Van der Waals constant

a (a t m L^{2} m o l^{- 2}) :

Join BYJU'S Learning Program

For one mole of a van der Waal's gas when b = 0 and T = 300 K, the pV vs 1V plot is shown below. The value of the van der Waal's constant a (atm L mol−2)

The correct option is C 1.5Van der Waal's equation of state is given as (p+n2aV2)(V−nb)=nRT Given n=1 and b=0 (p+aV2)V=RT⇒pV=RT−aV This is an equation of straight line between pV and 1V whose slope - a. Slope of the given graph is −a=20.1−21.63−2=−1.5⇒a=1.5

For one mole of a van der Waal's gas when b = 0 and T = 300 K, the $p V v s \frac{1}{V}$ plot is shown below. The value of the van der Waal's constant a ( $a t m L m o l^{- 2}$ )