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Question

For one mole of a Van der Waals gas when b = 0 and T = 300 K, the PV vs 1V plot is shown above. The value of the Van der Waals constant a (atm.L2.mol2) is

28866_dc0de7e338be4c38bcd42963efca3f48.png

A
1
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B
4.5
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C
1.5
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D
3
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Solution

The correct option is C 1.5
Vanderwaal's equation for 1 mole of gas is
(P+aV2)(Vb)=RT

But, b=0......(given)

(P+aV2)(V)=RT

PV=a×1V+RT

We know the basic general equation of straight line, y=mx+c

Slope =tan(πθ)=tan θ=a

So, tanθ=a=21.620.132=1.5

Option C is correct.

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