For one mole of a Van der Waals gas when b = 0 and T = 300 K, the PV vs 1V plot is shown above. The value of the Van der Waals constant a (atm.L2.mol−2) is
A
1
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B
4.5
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C
1.5
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D
3
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Solution
The correct option is C 1.5
Vanderwaal's equation for 1 mole of gas is
(P+aV2)(V−b)=RT
But, b=0......(given)
(P+aV2)(V)=RT
∴PV=−a×1V+RT
We know the basic general equation of straight line, y=mx+c