For one of the elements various successive ionisation energies are given below:
Igonisation Ener 1st 2nd 3rd 4th 5th
in $k J$ ${m o l}^{- 1}$ $577.5$ $1810$ $2750$ $11580$ $14820$
The element is:

magnesium

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aluminium

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silicon

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phosphorus

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Solution

The correct option is B aluminium
3rd ionisation energy $= 2750 k J$
4th ionisation energy $= 11580 k J$
4th ionsiation energy is much higher, it means removal of 4th electron is from the stable configuration, hence aluminium is the element

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k J

{m o l}^{- 1}

I.E	$1^{s t}$	$2^{n d}$	$3^{r d}$	$4^{t h}$	$5^{t h}$
	$577.5$	$1810$	$2750$	$11, 580$	$14, 820$

For one of the element various ionization enthalpies (in KJ $m o l^{- 1}$ ) are given below:

$\begin{matrix} I . E & 1^{s t} & 2^{n d} & 3^{r d} & 4^{t h} & 5^{t h} 577.5 & 1810 & 2750 & 11, 580 & 14, 820 \end{matrix}$

The element is

For one of the element various ionization enthalpies (in KJ $m o l^{- 1}$ ) are given below:

$\begin{matrix} I . E & 1^{s t} & 2^{n d} & 3^{r d} & 4^{t h} & 5^{t h} 577.5 & 1810 & 2750 & 11, 580 & 14, 820 \end{matrix}$

The element is

m o l^{- 1}

- 1

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Igonisation Ener	1st	2nd	3rd	4th	5th
in $k J$ ${m o l}^{- 1}$	$577.5$	$1810$	$2750$	$11580$	$14820$