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Byju's Answer

Standard XII

Chemistry

p and p Overlap

For oxy acid ...

Question

For oxy acid $H C l O_{x}$ if $x = y = z (x, y and z$ are natural number) then calculate the value of $(x + y + z)$ , Where
$x =$ Number of $O$ atoms
$y =$ Total number of lone pairs at central atom
$z =$ Total number of Pi(π) electrons in the oxy acid.

6.0

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Solution

For oxyacid $H C l O_{x}$
$x =$ number of $O$ atoms
$Let x = 2$
Hence, The structure of $H C l O_{2}$

$y =$ Total number of lone pair at central atom $= 2$
$z =$ Total number of pi (π) electrons in oxy acid $= 2$
Then the value of $(x + y + z) = 2 + 2 + 2 = 6$

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For oxy acid HClOx if x=y=z (x, y and z are natural number) then calculate the value of (x+y+z), Where x= Number of O atoms y= Total number of lone pairs at central atom z= Total number of Pi(π) electrons in the oxy acid.

For oxyacid HClOx x= number of O atoms Let x=2 Hence, The structure of HClO2 y= Total number of lone pair at central atom =2 z= Total number of pi (π) electrons in oxy acid =2 Then the value of (x+y+z)=2+2+2=6

For oxy acid $H C l O_{x}$ if $x = y = z (x, y and z$ are natural number) then calculate the value of $(x + y + z)$ , Where
$x =$ Number of $O$ atoms
$y =$ Total number of lone pairs at central atom
$z =$ Total number of Pi(π) electrons in the oxy acid.

For oxyacid $H C l O_{x}$
$x =$ number of $O$ atoms
$Let x = 2$
Hence, The structure of $H C l O_{2}$

$y =$ Total number of lone pair at central atom $= 2$
$z =$ Total number of pi (π) electrons in oxy acid $= 2$
Then the value of $(x + y + z) = 2 + 2 + 2 = 6$