Question

For parabola, $3y^2=16x$, focus and end points of latus rectum are :

• A. $(\frac{4}{3},0),(\frac{4}{3}.\pm \frac{8}{3})$
• B. $(\pm \frac{4}{3},0),(\frac{4}{3}.\pm \frac{8}{3})$
• C. $(\frac{4}{3},0),(\pm \frac{4}{3}.\frac{8}{3})$
• D. $(0,\frac{4}{3}),(\frac{4}{3}.\pm \frac{4}{3})$

Answer 1

Answer: (A)

$(\frac{4}{3},0),(\frac{4}{3}.\pm \frac{8}{3})$

focus i s$(a,o=(\frac{4}{3},0)$

end point of latus rectum $(a,2a)and(a,-2a)$

so answer is $(\frac{4}{3},\frac{8}{3})$ and $(\frac{4}{3},\frac{-8}{3})$