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Law of Mass Action

For PCl5g ⇌ P...

Question

For $P C l_{5} (g) ⇌ P C l_{3} (g) + C l_{2} (g),$ write the expression of $K_{c} .$

K_{c} = \frac{[P C l_{5}]}{[P C l_{3}] [C l_{2}]}

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K_{c} = \frac{[P C l_{3}] [C l_{2}]}{[P C l_{5}]}

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K_{c} = \frac{[P C l_{3}] [C l_{2}]}{[P C l_{5}]^{5}}

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K_{c} = \frac{[P C l_{3}]^{3} [C l_{2}]^{2}}{[P C l_{5}]^{5}}

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Solution

The correct option is B $K_{c} = \frac{[P C l_{3}] [C l_{2}]}{[P C l_{5}]}$
We know, for a reaction
$K_{c}$ = $\frac{Active mass of products}{Active mass of reactants}$
So, for the homogenous reaction, $P C l_{5} (g) ⇌ P C l_{3} (g) + C l_{2} (g)$
$K_{c} = \frac{[P C l_{3}] [C l_{2}]}{[P C l_{5}]}$

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Similar questions

P C l_{5} (g) ⇌ P C l_{3} (g) + C l_{2} (g),

K_{c} ?

P C l_{5} (g) ⇌ P C l_{3} (g) + C l_{2} (g),

K_{c} .

P C l_{5} (g) \Leftrightarrow P C l_{3} (g) + C l_{2} (g), K_{c}

P C l_{5} (g) \to P C l_{3} (g) + C l_{2} (g)

K_{c} = 1.8 \times 10^{- 7} .

Δ G^{0}

{P C l}_{3} (g) + {C l}_{2} (g) ⇌ {P C l}_{5} (g) + e n e r g y

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