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Standard XII

Physics

Reflection from an Open End

For photoelec...

Question

For photoelectric emission from a certain metal the cut off frequency is v. If radiation of frequency 2v impinges on the metal plate, the maximum possible velocity of the emitted electron will be (m is the electron mass).

\sqrt{\frac{h v}{(2 m)}}

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\sqrt{\frac{h v}{m}}

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\sqrt{\frac{2 h v}{m}}

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2 \sqrt{\frac{h v}{m}}

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Solution

The correct option is C $\sqrt{\frac{2 h v}{m}}$
Cutoff frequency = v
Work function = $ϕ$ = hv
Use, E=K.E + $ϕ$
$\frac{1}{2} m v^{2} = 2 h v - h v = h v$
$v = \sqrt{\frac{2 h v}{m}}$

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For photoelectric emission from a certain metal the cut off frequency is v. If radiation of frequency 2v impinges on the metal plate, the maximum possible velocity of the emitted electron will be (m is the electron mass).

The correct option is C √2hvmCutoff frequency = v Work function = ϕ = hv Use, E=K.E + ϕ 12mv2=2hv−hv=hv v=√2hvm

The correct option is C $\sqrt{\frac{2 h v}{m}}$
Cutoff frequency = v
Work function = $ϕ$ = hv
Use, E=K.E + $ϕ$
$\frac{1}{2} m v^{2} = 2 h v - h v = h v$
$v = \sqrt{\frac{2 h v}{m}}$