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Proof by mathematical induction

For positive ...

Question

For positive integer n, $10^{n - 2}$ > 81n, if

n > 5

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$n\geq$ 5

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n < 5

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n > 6

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Solution

The correct option is B
$n\geq$ 5

Check through option, the condition

$10^{n - 2}$ > 81n is satisfied if n ≥ 5.

Suggest Corrections

Similar questions

n^{4} < 10^{n}

n \geq 2

(n + 1)^{4} < 10^{n + 1}

n^{4} < 10^{n}

n \geq 2

(n + 1)^{4} < 10^{n + 1}

n

(\frac{1}{10})^{n} < 0.01

n > 2

(\frac{1}{10})^{n - 1} < 0.1

x (x + 1) + (x + 1) (x + 2) + . . . + (x + ¯ ¯¯¯¯¯¯¯¯¯¯¯ ¯ n - 1) (x + n) = 10 n

n,

x (x + 1) + (x + 1) (x + 2) + . . . . . + (x + ¯ ¯¯¯¯¯¯¯¯¯¯¯ ¯ n - 1) (x + n) = 10 n

n

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