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Question

For positive integers n1,n2 the value of the expression (1+i)n1+(1+i3)n1+(1+i5)n2+(1+i7)n2,i=1 is a real number if and only if

A
n1=n2+1
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B
n1=n21
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C
n1=n2
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D
n1>0,n2>0
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Solution

The correct option is A n1=n2+1
i1=i
i3=i
i5=i
i7=i
(1+i)n1+(1+i3)n1+(1+i5)n2+(1+i7)n2=(1+i)n1+(1i)n1+(1+i)n2+(1i)n2
As we know
(1+i)n1=C0+C1i+C2i2+C3i3+...... (a)
(1i)n1=C0C1i+C2i2C3i3+...... (b)
n1 is positive and constants are real
Adding (a) and (b)
(1+i)n1+(1i)n1=2(C0+C2i2+C4i4.....)
(1+i)n1+(1i)n1=2(C0C2+C4.....)=real
Similarly for n2
So
(1+i)n1+(1+i3)n1+(1+i5)n2+(1+i7)n2 is real for all n1 and n2 provided they are positive.

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