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Question

For r = 0,1,2,.............................. n,
CoCr+C1Cr+1+C2Cr+2............Cn−rCn=2nC(n+r) and hence C2o+C21+C22+............+C2a=2nCn

A
True
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B
False
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Solution

The correct option is A True
expnsion of (1+x)n=c0+c1x....
(x+1)n=c0xn+c1xn1
(1+x)2n=c0cr+c1cr+1=c2nn+r
now pur r=0
C2o+C21+C22+............+C2a=2nCn
similarly put r=1 in (ii)

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