For reaction- A- B- the rate of constant k 1 - A 1 e -E a 1 -RT and for the reaction- P- Q- the rate constant k 2 - A 2 e -E a 2 -RT- If A 1 - 10 8 - A 2 - 10 10 and E a 1 -600-E a 2 -1200- then the temperature at which k 1 - k 2 is-

The correct option is C 600 4.606 K According to Arrehenius equation, k=Ae^ E_a/RT if k_1=k_2 10^8e^ 600/RT=10^10e^ 1200/RT T=600/4.6 ...

You visited us 1 times! Enjoying our articles? Unlock Full Access!

Byju's Answer

Standard XII

Chemistry

Rate Constant

For reaction;...

Question

For reaction; $A \to B$ , the rate of constant $k_{1} = A_{1} e^{- E a_{1} / R T}$ and for the reaction; $P \to Q$ , the rate constant $k_{2} = A_{2} e^{- E a_{2} / R T}$ . If $A_{1} = 10^{8}, A_{2} = 10^{10}$ and $E a_{1} = 600, E a_{2} = 1200$ , then the temperature at which $k_{1} = k_{2}$ is:

600 K

No worries! We‘ve got your back. Try BYJU‘S free classes today!

300 \times 4.606 K

No worries! We‘ve got your back. Try BYJU‘S free classes today!

\frac{600}{4.606} K

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

\frac{4.606}{600} K

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is C $\frac{600}{4.606} K$
According to Arrehenius equation,
$k = A e^{\frac{- E_{a}}{R T}}$
if $k_{1} = k_{2}$
$10^{8} e^{\frac{- 600}{R T}} = 10^{10} e^{\frac{- 1200}{R T}}$
$T = \frac{600}{4.606} K$

Suggest Corrections

Similar questions

Q. For a reaction

A ⟶ B

, the rate constant

k_{1} = A_{1} e^{- {E a}_{1} / (R T)}

and for the reaction

X ⟶ Y

, the rate constant

k_{2} = A_{2} e^{- {E a}_{2} / (R T)}

A_{1} = 10^{8}, A_{2} = 10^{10}

and

{E a}_{1} = 600 c a l / m o l, {E a}_{2} = 1800 c a l / m o l

, then the temperature at which

k_{1} = k_{2}

is:

(Given:

R = 2 c a l / k m o l

)

Q. For two reactions, activation energies are

E_{a_{1}}

and

E_{a_{2}}

; rate constants are

k_{1}

and

k_{2}

at the same temperature. If

k_{1} > k_{2}

then

Q. A Chemical reaction occurs in three paths having rate constants

k_{1}, k_{2} & k_{3}

respectively. If

E a_{1}, E a_{2} a n d E a_{3}

are 4, 5 & 8kJ respectively and overall rate constant

k = \frac{k_{1} k_{3}}{k_{2}} . A s s u m i n g A_{a v} = \frac{A_{1} A_{3}}{A_{2}}

the overall energy of activation in kJ is ___.

A_{1}

B, Activation Energy

E a_{1}

A_{2}

C, Activation Energy

E a_{2}

E a_{2} = 2 E a_{1}

, then

k_{1}

and

k_{2}

are related as:

Q. A reactant (A) forms two products.

A k_{1} - \to B

, Activation energy

E a_{1}

A k_{2} - \to C

, Activation energy

E a_{2}

E a_{2} = 2 E a_{1}

, then

k_{1}

and

k_{2}

are related as:

Join BYJU'S Learning Program

For reaction; A→B, the rate of constant k1=A1e−Ea1/RT and for the reaction; P→Q, the rate constant k2=A2e−Ea2/RT. If A1=108,A2=1010 and Ea1=600,Ea2=1200, then the temperature at which k1=k2 is:

The correct option is C 6004.606KAccording to Arrehenius equation,k=Ae−EaRTif k1=k2108e−600RT=1010e−1200RTT=6004.606K

For reaction; $A \to B$ , the rate of constant $k_{1} = A_{1} e^{- E a_{1} / R T}$ and for the reaction; $P \to Q$ , the rate constant $k_{2} = A_{2} e^{- E a_{2} / R T}$ . If $A_{1} = 10^{8}, A_{2} = 10^{10}$ and $E a_{1} = 600, E a_{2} = 1200$ , then the temperature at which $k_{1} = k_{2}$ is:

The correct option is C $\frac{600}{4.606} K$
According to Arrehenius equation,
$k = A e^{\frac{- E_{a}}{R T}}$
if $k_{1} = k_{2}$
$10^{8} e^{\frac{- 600}{R T}} = 10^{10} e^{\frac{- 1200}{R T}}$
$T = \frac{600}{4.606} K$